Question

in ∆ace, b is mid point of ac, d is a mid point of ce,solve the x given bd =(5x+8)cm and ae= (4x+22)cm.​

Answer 1

Answer:

x = 1

Step-by-step explanation:

Given : B is the mid point of AC and D is the midpoint of CE .

CD/DE=CB/AC = 1 (because DC and AC are the mid point)

∴DE/CD + 1 = AC/CB + 1

(DE + CD)/CD = (AC + CB)/CB

CE/CD = AB/CB = 2

or , CD/CE = CB/AC

ΔACE and ΔBCD

∠C = ∠C                       (common on both the triangle)

CD/CE = CB/CA            (above proved )

by S.A.S ΔACE similar to ΔBCD

AC/BC = CE/CD = AE/BD

AE/BD = 2

(4x + 22)/(5x + 8) = 2

4x + 22 = 10x + 16

6x = 6

x = 1

Answer 2

Answer:

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Step-by-step explanation: