Question

in acidic medium Equivalent weight of kmn o4 will be​

Answer 1

Answer:

Explanation:

KMnO4 is a strong oxidising agent . In acidic medium, itself reduced to Mn2+ while in basic or neutral medium it reduced to MnO2, logic behind this is very simple , as acidic medium is also called as electron deficient medium . So there is no support from medium to reaction that why it compeleted its all deficiency of electron from other source (substrate) . While in basic medium (electron rich medium ) there is good support from the medium to reaction thatswhy it take only 3e from other source remaning electron provided by solution.

**In acidic medium**

MnO4- **+** **8**H+ **+ 5e = **Mn2+ **+ 4H2O**

from this reaction we can deduce that Mn7+ reduced to Mn2+ so **“ n factor” **for this reaction is 5

Eq.wt = molecular weight / n factor

So for KMnO4 molecular weight is 158.g

So Eq.wt = 158/5 = 31.6 g per equivalent