Question

in acidic medium moles of KMnO4 required to oxidise 1.5 moles of cu2s will be

Answer 1

equivalent of KMnO4 = equivalents of Cu2S

we know, equivalents = n- factors × number of moles

n - factor is defined as change in oxidation number in case of redox reaction .

number of mole of KMnO4 × change in oxidation = number of mole of Cu2S × change in oxidation

number of mole of KMnO4 × (+7 - +2) = number of mole of Cu2S× 2(+2 - +1)

number of mole of KMnO4 × 5 = number of mole of Cu2S ×

given, number of mole of Cu2S = 1.5

so, number of mole of KMnO4 = 2 × 1.5/5 = 0.6