In acidic medium, the equivalent weight of K,Cr,O,
(Mol. wt. =M) is
(a) M
(b) M/2
(c) M/3
(d) M/6
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Answer:
m/6
Explanation:
As each K2Cr2O7 contains 2 mole of Cr, so total change in oxidation is 6.
So, equivalent wt. of K2Cr2O7=M/6.
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