Math, asked by vaibhav4687, 2 months ago

In acute angled triangle ABC, seg AD perpendicular side BC, B-D-C, angle B=90°.
Prove that AC*2=AB*2 + BC*2- 2BC.BD​

Answers

Answered by prajwalchaudhari
0

Answer:

ABC, seg AD perpendicular side BC, B-D-C, angle B=90°.

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