Math, asked by pshubhampatel173, 3 days ago

In adjacent fig P and Q are midpoint of AB and AC respectively BC=7x.Find PQ​

Answers

Answered by Shivabhatt01
1

Step-by-step explanation:

In the adjacent figure, P and Q are points on the sides AB and AC respectively of a triangle ABC. PQ is parallel to BC and divides the triangle ABC into 2 parts, equal in area. The ratio of PA:AB=

93391

expand

Medium

Solution

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Correct option is C)

Given that Area of the Δ APQ = Area of PQCB

That means Area Δ ABC = 2 Area of Δ APQ

Since PQ ∥ BC

Therefore, Δ APQ is similar to Δ ABC

We know that ratio of the areas of two triangles is equal to the square of ratio of their sides in case of similar triangles.

Therefore,

Areaof△ABC

Areaof△APQ

=

AB

2

PA

2

AB

2

PA

2

=

Areaof△ABC

Areaof△APQ

=

2

1

AB

PA

=

2

1

Therefore, PA:AB = 1:

2

Answered by yroli386
0

Step-by-step explanation:

We have

(

AC

AQ

)=

9

3

=

3

1

(

AB

AP

)=

10.5

3.5

=

3

1

In ΔAPQ & ΔABC

(

AC

AQ

)=(

AB

AP

)

& ∠PAQ=∠BAC

Thus ΔAPQ∼ΔABC by SAS criterion.

Hence (

AC

AQ

)=(

BC

PQ

) (by cpst)

3

1

=(

BC

4.5

)

⇒BC=13.5cm.

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