In adjacent figure AD || BC and AD = BC. Prove that AB ||CD.
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To prove :- AB || CD
Given that :- AD = BC, <ABC = 80°
PROOF = In ∆ ABC and ACD
AD = BC ( Given )
AC = AC ( Common )
<ACB = <CAD ( Alternate interior angle )
So, ∆ABC ≈~ ∆ ACD
Hence AB || CD (By C.P.C.T)
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