Question

in adjacent figure find the magnitude of each of the three angles formed?

Answer 1

angles60 and 90 degree

Answer 2

Answer: Magnitude of each of the angles: 30, 60, 90

Solution:

For a horizontal plane total angle = 180

From the above figure,  sum of angles = x + 2x + 3x

                       Sum of angles = total angle of horizontal plane  

                         x+ 2x+ 3x  =  180

                         6x = 180

                         $x\quad =\quad \frac { 180 }{ 6 } \quad =\quad 30$

Therefore magnitude of each angles are 30 , 60, 90

Below figure,  sum of the angles = x + 2x + 3x

                       Sum of the angles = total angle of horizontal plane

                       x + 2x + 3x  =  180

                       6x = 180

                       X = 180/6 = 30

Therefore magnitude of each angles are 30 , 60, 90

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