In adjacent figure, If line l || line m, AP =3 ,PB=2,then find the values of AQ/QC and AR/RD...Please Solve fast & Send me Answer...I will give You Brainlist
Answers
SOLUTION:
Given AP=2.4 cm, AQ = 2 cm, QC = 3 cm, and BC = 6 cm.
By using Basic proportionality theorem,
AP/PB = AQ/QC
2.4/ PB = 2/3
2PB = 2.4 x 3
PB = (2.4x3)/2
PB = 1.2 x 3
PB = 3.6 cm
Now, AB = AP + PB
AB= 2.4 +3.6
AB= 6 cm
In A APQ and A ABC,
ZAPQ =ZABC (corresponding angles)
[PQ || BC, AB is transversal]
ZAQP =ZACB (corresponding angles)
[PQ || BC, AC is transversal]
A APQA ABC (AA similarity)
Therefore, AP/AB=PQ/BC= AQ/AC
[In similar triangles corresponding sides are proportional]
AP/ AB = PQ/BCZAPQ =ZABC (corresponding angles)
[PQ || BC, AB is transversal]
ZAQP=2ACB (corresponding angles)
[PQ || BC, AC is transversal]
A APQ ~ A ABC (AA similarity)
Therefore, AP/AB = PQ/BC=AQ/AC
[In similar triangles corresponding sides are proportional]
AP/ AB = PQ/BC
2.4/6 = PQ/6
PQ = 2.4 cm
Hence, AB = 6 cm and PQ = 2.4 cm.
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