In adjacent figure, PR > PQ and PS bisects ∠QPR. Prove that ∠PSR > ∠PSQ.
Attachments:
Answers
Answered by
64
Given:
PR > PQ & PS bisects ∠QPR
To prove:
∠PSR > ∠PSQ
Proof:
∠PQR > ∠PRQ — (i) (PR > PQ as angle opposite to larger side is larger.)
∠QPS = ∠RPS — (ii) (PS bisects ∠QPR)
∠PSR = ∠PQR +∠QPS — (iii)
(exterior angle of a triangle equals to the sum of opposite interior angles)
∠PSQ = ∠PRQ + ∠RPS — (iv)
(exterior angle of a triangle equals to the sum of opposite interior angles)
Adding (i) and (ii)
∠PQR + ∠QPS > ∠PRQ + ∠RPS
∠PSR > ∠PSQ [from (i), (ii), (iii) and (iv)]
Hope this will help you.......
HappiestWriter012:
great one madam
Answered by
22
Hope it will help you please mark it as brainliest
Attachments:
Similar questions