in adjoing figure ΔABC ≈ ΔADC. If <BAC =30° and <ABC=100° then <ACD isvequal to dash
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Given: AB=AC, ∠ACD=130
∠ACD+∠ACB=180 (Linear pair)
130+∠ACB=180
∠ACB=50
∘
Now, In △ABC,
∠ABC=∠ACB=50 (Isosceles triangle property)
Sum of angles = 180
∠ABC+∠ACB+∠BAC=180
50+50+∠BAC=180
∠BAC=80
∘
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