Question

in adjoining fig bisector of angle B angle C of traingle ABC interest at 'p' prove that angle BPC =1/2 angle BAC + 90

Answer 1

Answer:

your answer in the attachment

Answer 2

Answer:

$\huge\sf\purple{Answer-:!}$

Step-by-step explanation:

Given :

A △ ABC such that the bisectors of ∠ ABC and ∠ ACB meet at a point O.

To prove :

∠BOC=90o+21∠A

Proof :

In △ BOC, we have

∠1+∠2+∠BOC=180o     ....(1)

In △ ABC, we have,

∠A+∠B+∠C=180o

∠A+2(∠1)+2(∠2)=180o

2∠A+∠1+∠2=90o

∠1+∠2=90o−2∠A

Therefore, in equation 1,

90o−2∠A+∠BOC=180o

∠BOC=90o+2∠A