In adjoining figure AB=AC and AP=AQ prove i- ∆APC=~∆AQB ii- CP=BQ iii- angleAPC=angleAQB
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proof ,
in triangle APC and AQB
AC equals to BQ( oppo. side of a ll
gram are equal
AB equals to AC ( given)
AP equal to AQ ( given)
by sss rule of congruency
triangleAPC congruent to triangle AQB
CP equals to BQ (by c.p.c.t)
Angle APC equals to Angle AQB ( by c.p.c.t)
in triangle APC and AQB
AC equals to BQ( oppo. side of a ll
gram are equal
AB equals to AC ( given)
AP equal to AQ ( given)
by sss rule of congruency
triangleAPC congruent to triangle AQB
CP equals to BQ (by c.p.c.t)
Angle APC equals to Angle AQB ( by c.p.c.t)
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