in adjoining figure ab and ac are tangents to the circle with centre o and radius 8cm. If oa --is equal to 17cm then ac is...?
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7
Hey,
Join OC.
OC is perpendicular to AC.
In right triangle OCA,
OC^2 + AC^2 = OC^2
So, 8^2 + AC^2 = 17^2
Then, AC is 15 cm...
OC is 8 cuz it's the radius...
Feel free to ask any query
Join OC.
OC is perpendicular to AC.
In right triangle OCA,
OC^2 + AC^2 = OC^2
So, 8^2 + AC^2 = 17^2
Then, AC is 15 cm...
OC is 8 cuz it's the radius...
Feel free to ask any query
crystal42:
Its right
Answered by
4
Hey,
Join OC.
OC is perpendicular to AC.
In right triangle OCA,
OC^2 + AC^2 = OC^2
So, 8^2 + AC^2 = 17^2
Then, AC is 15 cm...
OC is 8 cuz it's the radius...
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