Question

in adjoining figure ABCD is a parallelogram of area 141cm square. P is a point on AB such that AP:PB=1:2.Find th
e area of triangle APD​

Answer 1

Step-by-step explanation:

Let R be the intersection of AC & BD. Apply Menelaus’s Theorem to triangle PBD with AC as the transversal. We have: (PQ/QD)*(DR/RB)*(BA/AP) = 1 or PQ/QD =AP/BA = 1/3 —-(2) whereas (Area Tr. APD)/(Area Tr.ABD)= (1/3) or Area Tr.APD = (1/3)*(81)= 27 m² ——(1)