Question

In adjoining figure ABCD is a quadrilateral in which ab is the longest side and CD is a smallest and prove that angle d is greater than angle b

Answer 1

Answer:

the answer is option b

Step-by-step explanation:

Given:

In quadrilateral ABCD, AB smallest & CD is longest sides.

Construction: Join AC

.

Mark the angles as shown in the figure..

In △ABC , AB is the shortest side.

BC>AB

∠2>∠4      −(i)

[Angle opposite to longer side is greater]

In △ADC , CD is the longest side

CD>AD

∠1>∠3    −(ii)

[Angle opposite to longer side is greater]

Adding (i) and (ii), we have

∠2+∠1>∠4+∠3

⟹∠A>∠C

Similarly, by joining BD, we can prove that

∠B>∠D