Question

In adjoining figure AE ⊥seg BC, seg DF ⊥ line BC,
AE = 4, DF = 6, than find A(△ABC
A(△DBC)
.

Answer 1

Step-by-step explanation:

Given : seg AE perpendicular side BC, AE =4, DF= 6

seg DF perpendicular line BC

To find : Ar (A ABC) / Ar (A DBC)

Solution:

Area of triangle = (1/2) * Base * Height

Ar (A ABC) = (1/2) * BC * AE

Ar (A DBC) = (1/2) * BC * DF

Vol 95

Ar (A ABC) / Ar (A DBC) = AE/ (1/2)* BC * DF (1/2)* BC

=> Ar (A ABC) / Ar (A DBC) DF = AE/

=> Ar (A ABC) / Ar (A DBC) = 4 / 6 => Ar (A ABC) / Ar (A DBC) = 2/3

Ar (A ABC) / Ar (A DBC) = 2/3

Answer 2

Step-by-step explanation:

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