Question

in adjoining figure angle abc is equal to 95 degree and Angle ACB is equal to 35 degree find angle bdc

Answer 1

Answer:

Ans:50°

Step-by-step explanation:

In triangle ABC

angle B=95°, angle C =35°

By angle sum property of triangle

angle A+angle B +angle C=180°

95°+35°+angle A =180°

130°+angle A=180°

angle A=180°-130°

=50°

Angle A=angle D =50°

(Angle in the same segment of circle are equal)

Answer 2

Given:

Angle ABC=95°

Angle ACB=35°

To find:
Angle BDC

Solution:

The required angle BDC is 50°.

The chord joining C and B forms the same angles at the circle's circumference.

The angles BDC and BAC are from the same chord and thus, of equal measure.

Angle BAC=Angle BDC

In the ΔABC, angle ABC+angle ACB+angle BAC=180°

Using the given measures,

95°+35°+angle BAC=180°

130°+ angle BAC=180°

angle BAC=180°-130°

angle BAC=50°

So, angle BDC=50°

Therefore, the required angle BDC is 50°.