in adjoining figure, AP perpendicular BC, AD|| BC, Then Find A( Triangle ABC): A( Triangle BCD).
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Answered by
139
Concept:
Area of triangle = 1/2 × b × h
ABC and BCD are triangle lying between same parallels and having the same base BC.
A1 :
Area of triangle ABC = 1/2 × BC × AP
A2:
Area of triangle BCD = 1/2 × BC × AP
Now
A1 : A2 = 1 : 1
Area of triangle = 1/2 × b × h
ABC and BCD are triangle lying between same parallels and having the same base BC.
A1 :
Area of triangle ABC = 1/2 × BC × AP
A2:
Area of triangle BCD = 1/2 × BC × AP
Now
A1 : A2 = 1 : 1
Answered by
50
ᴀʀᴇᴀ ᴏғ ᴛʀɪᴀɴɢʟᴇ = 1/2 × ʙ × ʜ
ᴀʙᴄ ᴀɴᴅ ʙᴄᴅ ᴀʀᴇ ᴛʀɪᴀɴɢʟᴇ ʟʏɪɴɢ ʙᴇᴛᴡᴇᴇɴ sᴀᴍᴇ ᴘᴀʀᴀʟʟᴇʟs ᴀɴᴅ ʜᴀᴠɪɴɢ ᴛʜᴇ sᴀᴍᴇ ʙᴀsᴇ ʙᴄ.
ᴀ1 :
ᴀʀᴇᴀ ᴏғ ᴛʀɪᴀɴɢʟᴇ ᴀʙᴄ = 1/2 × ʙᴄ × ᴀᴘ
ᴀ2:
ᴀʀᴇᴀ ᴏғ ᴛʀɪᴀɴɢʟᴇ ʙᴄᴅ = 1/2 × ʙᴄ × ᴀᴘ
ɴᴏᴡ
ᴀ1 : ᴀ2 = 1 : 1
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