in adjoining figure if AC= BD then prove that AB = CD
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Step-by-step explanation:
Here it is given that ∠A=90° and AB=AC,
if AB=AC then ∠B=∠C (angles opposite to equal sides)
now we know that
∠A+∠B+∠C=180° (triangle sum property)
90°+2∠B=180° (∠B=∠C)
2∠B=180-90
2∠B=90
∠B=45°=∠C
So, ∠B=∠C=45°
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