Question

in adjoining figure,P is the point in the interior of a parallelogram ABCD. Show that ar(ΔAPB)+ar(ΔPCD)=1/2ar(parallelogramABCD)

Answer 1

First we join the EF which pass through P then in llgm ABFE triangle ABC is half of llgm ABFE similarly PCD is half of llgm EFCD adding both eq