Question

* In adjoining figure PO, BC
AD 1 BC then find following
A( A POB)
ALA
A & PBC)
ASABO
(
TE
A( A ABC)
A)
(iv)
ACAA
ACS POC
Fig. 1.16
***
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Answer 1

Answer:

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Answer 2

Answer:

1) delta PQB and PBC have same hight PQ

A(deltapQB)/A(deltapBC)=BQ/BC. ....[tringales having equal hight]

2)delta PBC and delta ABC have same base BC

A(delta PBC) /A( delta BC) = PQ/AD. ....[ tringales having equal base]

3) delta ABC and delta ADC have same height AD

A(delta ABC)/A( delta ADC) =BC/DC ....[tringale having equal hight]

4) A(delta ADC)/A( delta PQC) =(DC×AD)/(QC×PQ)

...[Ratio of areas of two triangles is equal to the ratio of the product of their based and corresponding heights].