In adjoining figure, PQ II RS. If angle 1 = (2a + b)° and angle 6 = (3a - b)º
then find the measure of angle2 in terms of b.
please explain and take your time to answer.
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Answered by
2
Answer:
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Step-by-step explanation:
Answered by
6
Answer:
Here, PQ parallel to RS and I is a transversal.
⇒∠2=∠6=(3a−b)
o
(1) [ corresponding angles ]
Now,
∠1+∠2=180
o
[linear angles]
∵∠1=(2a+b)
o
∴∠2=180
o
−(2a+b)
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....(2)
From equation 1 and 2, we get
⇒(3a−b)
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=180
o
−(2a+b)
o
⇒3a−b+2a+b=180
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⇒5a=180
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⇒a=
5
180
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⇒a=36
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∴a=36
o
Now,
⇒∠2=(3a−b)
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[ from equation 1]
⇒∠2=(3×36−b)
o
⇒∠2=(108−b)
0
hence, option C is correct
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