Question

In algebra

If x2+y2=8 and xy=7, then (x+y)2=?

Answer 1

x²+y² = 8

xy = 7

( x + y)² = ( x + y ) (x + y)

= ( x² + y² + 2xy )

= 8 + 2 ( 7 )

= 8 + 14

= 22

Hope the solution is clear to you!!

Answer 2

Step-by-step explanation:

Given

x^2 + y^2 =8

and xy = 7

we have to find the value of ( x + y ) ^2

it is in the form of ( a + b ) ^ 2 = a ^2 + b^2 + 2ab

so ( x +y ) ^ 2 = x^2 + y ^2 +2xy

substituting the values

we may get

( x + y) ^2 = 8 + 2 x7 = 8+ 14 = 22