Question

in alpha particle 2he4 is revolving in a circular orbit of radius 3.14 A with speed of 3*10^6 m/s then equivalent current​

Answer 1

Answer:

0.487 mA

Explanation:

The charge associated with alpha particle is 2×1.6×10^19 C

The time period of rotation is $\frac{2*3.14*r}{v}$ s

Current is $\frac{2*1.6*10^1^9*3*10^6}{2*3.14*3.14*10^-^1^0}$ A

= 0.487 mA

Answer 2

Explanation:

0.487 mA

Explanation:

The charge associated with alpha particle is 2×1.6×10^19 C

The time period of rotation is \frac{2*3.14*r}{v}

v

2∗3.14∗r

s

Current is \frac{2*1.6*10^19*3*10^6}{2*3.14*3.14*10^-^1^0} A

= 0.487 mA