In alternating voltage of 220 volt is applied across a device x a current of 0.25 ampere flows which lax behind the applied voltage and phase bye bye bye to radian
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When an alternating voltage of 220V is applied across a device X, a current of 0.25A flows through the circuit and is in phase with the applied voltage. When the same voltage is applied across another device Y the same current flows through the circuit but it leads the applied voltage by /2 rad.
(a) Name the devices X and Y.
(b) Calculate the current flowing in the circuit when same voltage is applied across the series combinations of X and Y.
answer : (a) X is resistor and Y is capacitor.
(b) I = 0.25A , V = 220 volts
R = Xc , as the same current flows in both cases, when both are connected in series.
so, net impedance, Z = √(R² + Xc²)
= √(R² + R²) = √2R
= √2 (V/I) [ from Ohm's law, V = IR ]
= √2 × 220/0.25
= 1244.5 ohm
Voltage applied is same. so, current through it is V/Z = 220/1244.5 = 0.17677A
(a) Name the devices X and Y.
(b) Calculate the current flowing in the circuit when same voltage is applied across the series combinations of X and Y.
answer : (a) X is resistor and Y is capacitor.
(b) I = 0.25A , V = 220 volts
R = Xc , as the same current flows in both cases, when both are connected in series.
so, net impedance, Z = √(R² + Xc²)
= √(R² + R²) = √2R
= √2 (V/I) [ from Ohm's law, V = IR ]
= √2 × 220/0.25
= 1244.5 ohm
Voltage applied is same. so, current through it is V/Z = 220/1244.5 = 0.17677A
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