Question

In Ammonia molecule the bond angle is 107 and in water molecule it is 104°35, although in both the central atoms are sp3 hybridized Explain????

Answer 1

Answer:

here the concept of lone pairs work the Next in NH3 have a single lone pair but in water the O has 2 lone pair the lone pair — lone pair repulsion is greater than the bond pair bond pair repulsion between the H bonds therefore this reduces the bond angel in H2O

Explanation:

I hope it's help for you

Answer 2

The bond angle in ammonia is 107° whereas in water it’s 104°35 even though both are sp3 hybridized because of the effect of lone pairs.

• The force of repulsion between two lone pairs is greater than the repulsion force between two bond pairs.
• In repulsion forces BP-BP < BP-LP < LP-LP.
• In ammonia there is only one lone pair present, so the force of repulsion between lone pair and bond pair is not that great but still greater than the bond pair-bond pair force of repulsion due to which its bond angle is 107°C
• Whereas in the water molecule two lone pairs cause lone pair-lone pair force of repulsion which is the greatest among all three types, and so it has a smaller bond angle of 104°35.

∴ The bond angle in a water molecule is 104°35 even though it is sp3 hybridized just like ammonia, because of the effect of lone pair on repulsion force.