Question

In ammonia, nitrogen and hydrogen are always present in the ratio 14:3 by mass.State the law which explains the above statement. (b) During the formation of ammonia, what mass of hydrogen gas would be required to react completely with 42g of nitrogen gas?​

Answer 1

Answer:

a In ammonia NH3 N and H present in fixed ratio which supports the law of definite or constant proportions. This law states “a pure chemical compound always consists of the same elements that are combined together in a fixed proportion by mass”. b Molecular mass of ammonia NH3 = mass of N + mass of H = 14 + 3 × 1 =17 To react with 14 g N mass of H required = 3 g Therefore to react with 42 g N mass of H required = 3/ 14 ×42 = 9g.

Answer 2

Answer:

b Molecular mass of ammonia NH3 = mass of N + mass of H = 14 + 3 × 1 =17 To react with 14 g N mass of H required = 3 g Therefore to react with 42 g N mass of H required = 3/ 14 ×42 = 9g.