Question

in AMT-4cm ,MT-6cm a =5cm and AMT -POR if =8cm then. find the lengths of remaining sides of PQR​

Answer 1

Answer:

Solution:

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides

Given that,

Sides of two similar triangles are in the ratio 4: 9.

We know that,

The ratio of the areas of two similar triangles = square of the ratio of their corresponding sides

= (4: 9)2

= 16 : 81

Thus option (D) 16: 81 is the correct answer.

Answer 2

Answer:

Given that:

QP=8cm,PR=6cm and SR=3cm

(I) In △PQR and △SPR

∠PRQ=∠SRP (Common angle)

∠QPR=∠PSR (Given that)

∠PQR=∠PSR (Properties of triangle )

∴△PQR∼△SPR (By AAA)