In an a Arithmatic progression the 3rd term is 3 and 5th term is -11 find the 50th term
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1
Answer:
-326
Step-by-step explanation:
Here we have to mainly use the formula
" tn = a+(n-1)d"
Hence , first equation we get ,
3= a + (3-1)d
i.e 3 = a+ 2d
second equation we get ,
-11= a + 4d
on solving both equation simultaneously , we get
a = 17 and d = -7
therefore,
t50 = 17 + (50-1)(-7)
= 17 + (-343)
= -326
I think it will surely help you .
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