Physics, asked by sukhjitkainth03, 5 months ago

In an a.c. series LCR circuit, the instantaneous current is maximum and
impedance is minimum. The given circuit behaves as:
(a) Pure inductor (b) Pure capacitor (c) Pure resistance d) None of the above​

Answers

Answered by Rizakhan678540
22

Explanation:

The circuit element connected to the AC source will be pure resistance. In pure resistive AC circuit, voltage and current are in the same phase.

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Answer = pure resistance

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Answered by SahiliDessai1998
0

Answer:

In an A.C. series LCR circuit, the instantaneous current is maximum and

impedance is minimum. The given circuit behaves as option (a) Pure inductor.

Explanation:

Pure capacitor:

When the capacitor's potential difference is 90° behind the current. A 90° phase discrepancy is visible. The flow of current will be reduced.

Pure inductor:

When current is 90° slower than the inductor's potential difference. A 90° phase discrepancy is visible. The flow of current will be reduced.

When the current and potential difference are in phase, a resistor is considered pure.

In other words, only when instantaneous voltage is at its highest will instantaneous current reach its maximum or minimum value.

A tank circuit, resonant circuit, or tuned circuit is a combination of an inductor and a capacitor. Signals can be produced or captured using it. Oscillator, filter, frequency mixer, etc. are only a few of its uses. The ac is sinusoidal. As a band-pass filter, it will operate. At the resonant frequency, it possessed no impedance.

To know more about LCR circuit, click on the link below,

https://brainly.in/question/1954243

To know more about LCR circuit, click on the link below,

https://brainly.in/question/182836

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