Question

In an A.P 17 th term is 7 more than its 10th term . Find the common difference.

Answer 1

Answer:

We know that, for an A.P series

an = a+(n−1)d

a17 = a+(17−1)d

a17 = a +16d

In the same way,

a10 = a+9d

As it is given in the question,

a17 − a10 = 7

Therefore,

(a +16d)−(a+9d) = 7

7d = 7

d = 1

Therefore, the common difference is 1.

Hope it helps you .

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Answer 2

Answer:

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Let the first term of the A.P be a and the common difference d.

tn= a + (n-1)d

t17 = a + (17-1)d

t17=a+16d

t10=a+(10-1)d

t10=a+9d

From the given condition and from (1) and (2)

a+16d=a+9d +7

16d-9d=7

7d=7

d=1

ans. The common difference is 1