Math, asked by Aayesha99931, 9 months ago

In an A.P. 17th term is 7 more than its 10th term . Find the commom differences

Answers

Answered by nielkrishna2005
1

Answer:

It is simple i will show you

A17= 7+10th term

a+(17-1)d = a+(10-1)d

a+ 16d = 7+a+ 9d

a-a+16d-9d= 7

             7d= 7

               d= 7/7

               d= 1

Hope you understood the answer

Answered by Anonymous
3

\bold{\huge\red{\boxed{{{QUESTION}}}}}

The 17th term of an AP exceed is 10th term by 7. find the common differnce.

\bold{\huge\red{\boxed{{{ANSWER}}}}}

Let \: a \: be \: the \: first \: term \: and \\  \: d \: be \: the \: common \: diffrence \: of \: the \: given \: AP \\  \\ Now,  \: according \: to \: the \: question \: a17 = a10 + 7 \\  =  > a17 - a10 = 7 \\  =  > a + (17 - 1)d - a + (10 - 1)d = 7 \\ ( an = a + (n - 1)d) \\  \\  =  >  \:  \: (a + 16d) - (a + 9d) = 7 \\  =  >  \: 7d \:  = 7 \\  =  >  \:  \: d = 1 \\  \\ Hence,  \: the \: common \: diffrence \: of \: this \: ap \: is \: 1.

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