Question

In an A.P 24th term twice the 10th term
and the 6th term
is 10. write the first three
term of
A.P.

​

Answer 1

Step-by-step explanation:

Its a 24th terms so that term will be

t²⁴=a+(n-1)d

This is the formula of tⁿ=a+(n-1)d, where a is the first term and n is the 24th of t and d is the common difference between each terms of an AP.

According to this question(ATP)

t24=2 x t10

=)a+(24-1)d=2a + 2d(10-1)

=)23d-18d=2a-a

=)5d=a.......(1)

Since

T6 is given, 10

So,

a+(6-1)d=10

Substituting a by 5d. [from eq. (1)]

=)5d +5d=10

=)10d=10

=)d=1

Now that we found d, the common difference of the AP, we will put d=1 in the eq. (1)

i.e. 5 x 1= a

So we got a=5..

Since common difference is 1 so we knows the first 3 terms of AP, i.e.

5, 6, 7