In an A.p. 7th term is 9 and 9th term is 7, then find 16th term
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a +6d=9 and a + 8d=7
so by elimination methid
a + 8d = 7
a + 6d =9
- - -
------------
0+ 2d = -2
so,d = -1
and
a + 8d =7
a +8(-1) =7
a -8 =7
a = 7+8
a = 15
d = -1
in 16th term
a+ 15d
15+15(-1)
15-15=0
so by elimination methid
a + 8d = 7
a + 6d =9
- - -
------------
0+ 2d = -2
so,d = -1
and
a + 8d =7
a +8(-1) =7
a -8 =7
a = 7+8
a = 15
d = -1
in 16th term
a+ 15d
15+15(-1)
15-15=0
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