In an A.P., a=10 and d= -3 then find its first four terms.
Answers
Answered by
8
Answer:
a=10 d= -3
a1=10
a2=a+d=10+(-3) =10-7=3
a3=a+2d=10+2(-3) =10-6=4
a4=a+3d=10+3(-3) =10-9=1
this is your answer
Answered by
2
Answer:
T1=10
t2= t1d =10+(-3)=
10-3
=7
t3=T2+d=7+(-3)=
7-3=
=4
t4= t3+d=4+(-3)
4-3=
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