In an A.P. a, + , + 2,……..the difference between 10th and 15th term is 200.Find the value of d.
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According to the question
a15 - a10 = 20
In an A.P
frist term = a
second term = a + d
third term = a + 2d
so they can be written as
a15 = a + 14d
a10 = a + 9d
therefore,
a15 - a10 = 200
a + 14d - ( a + 9d ) = 200
a + 14d - a - 9d = 200
5d = 200
d = 40
Hence the value of d is 40
hope it helps you
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