Question

In an A.P. a=7, d=3, n= 8 then a =
(a) 28 (b) 38 (©) 18​

Answer 1

$\huge{\blue{\boxed{\green{\underline{\orange{\mathbb{Question✩}}}}}}}$

a=7, d=3, n=8 find an term of A.P

(a) 28 (b) 38 (©) 18

$\bold{\huge\pink{\boxed{{{answer (a)➺ 28}}}}}$

STEP BY STEP SOLUTION :-

$\huge \mathcal \color{maroon}{Given :-}$

$\\ a \: = 7 \\ d = 3 \: \: \\ n = 8 \:$

$\huge \mathcal \color{maroon}{To \: find :-}$

${}^{a}n = ?$

$\huge \mathcal \color{maroon}{Solution :-}$

${}^{a} n = a + (n - 1)d \\ (by \: putting \: the \: value \: of \: a,d \: and \: n) \\ ⟹7 + (8 - 1)3 \\ ⟹7 + (7 \times 3) \\ ⟹7 + 21 \: \: \: \: \: \: \\ ⟹an=28 \: \: \: \: \: \: \: \: \: \:$

$\huge \mathcal \color{maroon}{Information :- }$

$Here, \: \\ \: \: ➯ \: a=1st \: term \: of \: \: AP \\ ➯ \: d = common \: diffrence \\ ➯ \: n = number \: of \: terms \\ ➯ \: {}^{a} n = last \: term \\ ➯ \: formula \: used = a + (n - 1)d$

Answer 2

Step-by-step explanation:

HEY MATE.........

$given \\ \\ a = 7 \\ d = 3 \: and \: \\ \\ n = 8 \\ \\ \\ solution \: \\ \\ by \: using \: an = a + (n - 1)d \\ \\ \\ therefore \\ \\ a8 = a + 7d \\ \\ 7 + 7 \times 3 = 28$

HOPE IT HELPS YOU