In an A.P a10= 20, a20=10.Find a30 ?
Plz ans this question. Who will ans this question I will make them as 'Brainlist'!
Answers
Answered by
2
Answer:
a30 = 0
Step-by-step explanation:
a10 = 20 --> a + 9d = 20 ----> (1)
a20 = 10 --> a + 19d = 10 ---->(2)
Subtracting (1) from (2),
10d = -10
d = -1
Substituting d value in (1),
a - 9 = 20
a = 29
Therefore,
a30 = a + 29d = 29 +29(-1) = 29 - 29
a30 = 0
Hope it is useful...
Answered by
0
a10= a+9d= 20......(i)
a20= a + 19d= 10.....(ii)
Subtracting (i) from (ii)
10d= -10
d= -1
Putting value of d in (i)
20= a -9
hence a= 29
hence a30 = a+29d
29-29=0
Similar questions