In an A.P, a2 =7 ¾
a29 = 1, a =
an = -6 ½, then n =
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the three numbers would have formed an AP. ... The numbers of divisors of 1029, 1547 and 122 are in (a) 1/3 (c) 3/4 (a) AP (b) GP (c) HP ( d) none ... If a1 , a2 , a3 , a4 are in HP, then 1 3 ...
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