In an A.P given a=5,d=3,an=50,find n and sn
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Step-by-step explanation:
Given, a=5,d=3,a
n
=50
⇒a+(n−1)d=50
⇒5+(n−1)3=50
⇒5+3n−3=50⇒3n=48⇒n=16
∴S
16
=
2
16
[2a+(16−1)d]=8[2×5+15×3]=440
Hence, n=16,S
16
=440
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