in an a.p given a7=30 and a10= 42 find a and sn
Answers
Answered by
0
Step-by-step explanation:
a7=a+6d=30
a10=a+9d=42.
=>a+9d-a-6d=42-30
=>3d=12=>d=4
=>a+6(4)=30
=>a=6
Answered by
3
Answer:
a = 6
Sn = 2n^2 + 4n
Step-by-step explanation:
a7 = 30
a + 6d = 30 ...........(i)
a10 = 42
a + 9d = 42 .............(ii)
Solving (i) and (ii)
-3d = -12
d = 4
putting d in (i)
a = 6
Sn = n/2 {2a + (n - 1)d}
= n/2 {12 + 4n - 4}
= n{4 + 2n}
Sn = 2n^2 + 4n
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