in an A.P. if a = 2 and t5 = 12, find t2, t3, t4....
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Hi dear
here is your answer!!!
I took t as a
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arshiya13258:
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Hey Mate here's the solution.
a = 2
t5 = a+4d = 12 ---- 1 eq.
ATQ,
Putting value of a in eq. 1,
a+4d = 12
2+4d = 12
4d = 12-2
d = 10/4 = 5/2
Value of
t2 = a+d = 2+5/2 = 9/4
t3 = a+2d = 2+2*5/2 = 2+5 = 7
t4 = a+3d = 2+3*5/2 = 19/2
Hope it will help you.....
a = 2
t5 = a+4d = 12 ---- 1 eq.
ATQ,
Putting value of a in eq. 1,
a+4d = 12
2+4d = 12
4d = 12-2
d = 10/4 = 5/2
Value of
t2 = a+d = 2+5/2 = 9/4
t3 = a+2d = 2+2*5/2 = 2+5 = 7
t4 = a+3d = 2+3*5/2 = 19/2
Hope it will help you.....
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