In an A.P if a=5, d=3 then n, Sn respectively
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• n = 16
• Sn = 440
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Given :-
• An AP whose a = 5 , d = 3 , an = 50
To Find :-
• n, Sn
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★ Let's find n
=> a + (n -1)d = 50
=> 5 + (n - 1)3 = 50
=> 5 + 3n - 3 = 50
=> 2 + 3n = 50
=> 3n = 50 - 2
=> 3n = 48
=> n = 48/3
=> n = 16
★ Now, let's find Sn
• Sn = n/2 {2a + (n - 1)d}
Sn => 16/2 {2(5) + (16 - 1)3}
Sn => 8 {10 + 45}
Sn => 8 × 55
Sn => 440
Hence, n and Sn are 16 and 440 respectively.
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