in an A.P. ,if a16=p,then find the sum of first 31 terms
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let a is the first and d is the common difference of AP
16th term = P
a + (16 - 1)d = P
a + 15d =P ---------(1)
sum of 31 terms =31/2{2a +(31-1)d }
=31{a +15d}
from equation (1)
sum 31 terms =31P
16th term = P
a + (16 - 1)d = P
a + 15d =P ---------(1)
sum of 31 terms =31/2{2a +(31-1)d }
=31{a +15d}
from equation (1)
sum 31 terms =31P
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