in an A.P if T1 =3,T2=5,then S3=?
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a=3, a+d=5 then d=2 then S3=10
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T1=3 t2=5 d=2 T3=7
Sn=n/2[2a+(n-1)d]
S3=3/2[6+(3-1)2]
S3=3/2[6+(2)2]
S3=3/2[6+4]
S3=3/2*10
S3=3*5
S3=15
Sn=n/2[2a+(n-1)d]
S3=3/2[6+(3-1)2]
S3=3/2[6+(2)2]
S3=3/2[6+4]
S3=3/2*10
S3=3*5
S3=15
Jayjain1:
thnx very much bro
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