Question

in an a. p if the first term is 4 9th term is 20 then 15 th term is​

Answer 1

Answer:

a = 4

a + 8d = 20

from above we get...

a = 4

d= 2

hence

15th term is

= 4 + 14 (2)

4 + 28

32

hope it helpss.....

Answer 2

Answer:

ACCORDING TO QUESTION:-)

1st term = 4

And

9th term = 20

let a be the first term of the AP and d be the common difference of AP.

So,

Here,

$a = 4 \\ and \\ a_9 = a + 8d = 20$

Solving both

We get:-)

$a = 4 \\ and \: \\ d = 2$

Now,

$15 \: term \\ i.e. \\ a_{15 }= a + 14d \\ = 4 + 14 \times 2 \\ = 4 + 28 \\ = 32$