Question

In an A.P. second and fifth terms are the roots of the equations.
x2 - 4x - 32 = 0 find these numbers.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

${x}^{2} - 4x - 32 \\ {x }^{2} - 8x + 4x - 32 \\ x(x - 8) + 4(x - 8) \\ (x + 4)(x - 8) = 0 \\ so \: x + 4 = 0 \\ x = - 4 \\ and \: \: x - 8 = 0 \\ x = 8$

So, the roots are -4and 8

a2 = -4

a5 = 8