In an A.P sixth term is one more than twice the third term the sum of the fourth and fifth is five terms the second term find the tenth term of the A.P
Answers
Answered by
1
Answer:
Tenth term of the A.P is 29.
A6 = a+5d = 1+ 2(a+2d)
a+5d = 1+2a+4d
5d-4d = 2a-a+1
d = a+1
a+3d+a+4d = 5(a+d)
2a+7d=5a+5d
7d-5d=5a-2a
2d=3a
putting the value of d ,
2(a+1) =3a
2a+2=3a
3a-2a=2
a = 2
So, d=2+1=3.
Now, A10= a+9d
= 2+(9×3)
= 2+27= 29.
Answered by
0
Answer:
Tenth term of the A.P is 29.
A6 = a+5d = 1+ 2(a+2d)
a+5d = 1+2a+4d
5d-4d = 2a-a+1
d = a+1
a+3d+a+4d = 5(a+d)
2a+7d=5a+5d
7d-5d=5a-2a
2d=3a
putting the value of d ,
2(a+1) =3a
2a+2=3a
3a-2a=2
a = 2
So, d=2+1=3.
Now, A10= a+9d
= 2+(9×3)
= 2+27= 29.
Step-by-step explanation:
Similar questions