Question

In an A.p ,sn=5n^2+11n then find Tn​

Answer 1

Answer:

$s_{1} = 5 + 11 = 16 = first \: \: term \: \: of \: \:a .p. \\ \\ s_{2} = 5 \times 4 + 11 \times 2 = 20 + 22 = 42 \\ \\ = > common \: \: difference \: = 42 - 16 = 26 \\ \\ = > t_{n} = a + (n - 1)d \\ \\ = > t_{n} \: = 16 + (n - 1)26 = 26n - 10$

Answer 2

s1 =5+11=16=firsttermofa.p.

ss =5×4+11×2=20+22=42

=>commondifference=42−16=26

=>tn=a+(n−1)d

=>t n=16+(n−1)26=26n−10